-4.9x^2+4.8x+0.1=0

Solution for -4.9x^2+4.8x+0.1=0 equation:

-4.9x^2+4.8x+0.1=0

a = -4.9; b = 4.8; c = +0.1;
Δ = b2-4ac
Δ = 4.82-4·(-4.9)·0.1
Δ = 25
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{25}=5$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(4.8)-5}{2*-4.9}=\frac{-9.8}{-9.8}
=1
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(4.8)+5}{2*-4.9}=\frac{0.2}{-9.8}
=-0.2/9.8
$